How many combinations?

Numbers from 1-39, combos of 6 numbers, order doesn't matter (123456 = 123465).
So, 123456, 123457,123458.... I didn't bother to think cause I know there's a formula for it, I was thinking 39^39 or something?

Numbers from 1-39, combos of 6 numbers, order doesn't matter (123456 = 123465).
So, 123456, 123457,123458.... I didn't bother to think cause I know there's a formula for it, I was thinking 39^39 or something?

This is just a simple combinations problem (Nearly equivalent to the NZ lotto draw problem actually)

n! / (k! * (n-k)!) is the formula you want, where n = 39 and k = 6

http://en.wikipedia.org/wiki/Combination

This is just a simple combinations problem (Nearly equivalent to the NZ lotto draw problem actually)

n! / (k! * (n-k)!) is the formula you want, where n = 39 and k = 6

http://en.wikipedia.org/wiki/Combination

Sooo the lottery is stacked up to 6200 million CLP (around 13 million dollars) right now, and buying every possible combination is ~2300 million (4.8m dollar). So if you were to buy every combination you'd most likely profit (it's rarely won by more than 2 people).

Numbers from 1-39, combos of 6 numbers, order doesn't matter (123456 = 123465).
So, 123456, 123457,123458.... I didn't bother to think cause I know there's a formula for it, I was thinking 39^39 or something?

3.2 million combinations, roughly.

you didn't mention if the numbers can repeat or not...but since it's the lottery, it doesn't repeat right?

you didn't mention if the numbers can repeat or not...but since it's the lottery, it doesn't repeat right?

they don't, which it's why it's 3.2million.

You guys really only have 39 numbers lol? Damnnn.

Yeah charizard is correct.

Yea, combination formula.

nCr
39C6
3262623

go out and buy them all!