Count to 10

I've been reading some depressing stories about programming when a bit caught my eye:

If you can successfully write a loop that goes from 1 to 10 in every language on your resume, can do simple arithmetic without a calculator, and can use recursion to solve a real problem, you're already ahead of the pack!

Makes me wonder, how many ways can Southperry count to 10? Anything that a computer can run to print an output counts. JavaScript to C++. Python to Assembly.

Guidelines:

• Using a language multiple times is fine, as long as the methodologies are different.
  
• The quote says "loop". Don't hardcode it in. eg: Don't type out 1 through 10 and have the program print it out.
  
• Simpler, more elegant solutions are better. Strive for those.
  

Define "every language" does that include the obsolete ones?

Unless it's something that no one has ever heard of, yes.

Nevermind. If it's a 'language' in even the loosest sense it counts.

Got bored after the first three, since most others are just variations of these.
VB

 Spoiler

Code:

Sub v1()
    While x <= 10
        Debug.Print x
        x = x + 1
    Wend
End Sub

Sub v2()
    For x = 1 To 10
        Debug.Print x
    Next
End Sub

Sub v3()
    Do Until x = 10
        x = x + 1
        Debug.Print x
    Loop
End Sub

TSQL

 Spoiler

Code:

declare @x tinyint

set @x = 1
while @x <= 10
BEGIN
    print @x
    set @x = @x + 1
END


declare @x tinyint

set @x = 1
while @x <= 10
BEGIN
    print @x
    select @x = @x+1
END

C

 Spoiler

Code:

void v1()
{
    short int x;
    for ( x =1; x <= 10; x++)
    {
        printf( "%d\n", x);
    }
}

void v2()
{
    short int x=0;
    while ( x <= 10 )
    {
        x++;
        printf( "%d\n", x);
    }
}

void v3()
{
    short int x=0;
    while ( 1 )
    {
        if ( x <= 10)
        {
            x++;
            printf( "%d\n", x);
        }
        else
            break;
    }
}

I would give you a brohug if i were in front of you.

This reminded me that i had to look up ways to find how to know when a number is even or odd while making algorithms (And later coding it), and now i remembered how to calculate multiples of any number to boot too

Im still fairly new to programing and have to restart my education of it because of a few problems that i won't bother mention, but someone would be nice to explain this to me? "printf( "%d\n", x)" only one that didn't understand exactly what it says (I can guess, sort of, but i would rather know exactly what it is).

I would give you a brohug if i were in front of you.

This reminded me that i had to look up ways to find how to know when a number is even or odd while making algorithms (And later coding it), and now i remembered how to calculate multiples of any number to boot too

Im still fairly new to programing and have to restart my education of it because of a few problems that i won't bother mention, but someone would be nice to explain this to me? "printf( "%d\n", x)" only one that didn't understand exactly what it says (I can guess, sort of, but i would rather know exactly what it is).

printf can be read as "print formatted", that is, printing something to the output in a formatted manner. You can dictate that the thing you print be an interger (d), a floating point value (f), a string (s) or possibly more. Basically, it's a function, it receives order to do something and HOW to do it, then do it.

In your example: printf("%d\n", x) says to print x (whatever it may be) as an integer (%d part) - so it probably will cut off the decimal part if x is a floating point value.
The \n part, if I'm not mistaken, universally means "insert a newline" where \ is the escape sequence so that n could mean new (and not the literal character n).

As for the actual topic, I only know Java as of now (so probably I can do it in C and C++ after a 10-minute session digging up?), and here's the most obvious ways:

Code:

for(int i=1; i <=10; i++) {
   System.out.println(i);
}

Code:

int i = 1;
do {
   System.out.println(i++);
} while (i <= 10);

Code:

public static void addOne(int i) {
   if(i < 10) {
      i++;
      System.out.println(i);
      addOne(i);
   }
}

This reminded me that i had to look up ways to find how to know when a number is even or odd while making algorithms (And later coding it), and now i remembered how to calculate multiples of any number to boot too

Modulo for both?

Im still fairly new to programing and have to restart my education of it because of a few problems that i won't bother mention, but someone would be nice to explain this to me? "printf( "%d\n", x)" only one that didn't understand exactly what it says (I can guess, sort of, but i would rather know exactly what it is).

C is a low level language, it does not have any natural ways to print values without explicitly casting them into a character string via a format conversion function like printf. The other languages you can just say print @variable and the engine knows to bring the value of the variable, but with C you have to be more specific, because print requires a character string and x is a number, therefore you need to convert x into a character string to print it, either via that function, or a more torturous route such as creating a character array and printing to that array the value of the variable. Could've possibly done a print( itoa(x)); as well.

R

seq(1:10)

Matlab

for(i=1:10)
i

C++

for(i=1;i<=10;i++)
{
cout<<i;
}

C++ Recursive

void main()
{
printseq(1,10);
}
void printseq(int number, int end)
{
cout<< number;
if(number <10)
{
printseq(number+1,end);
}

}

The java one looks almost exactly like C++ cept it uses System.out.println(i); instead of cout<<i;

Modulo for both?

Pretty much yes. I remember that i was taught that but forgot about it, while i got caught up recently on a problem that needed to find if a number was Odd and Even and could not remember the method to do so.

C is a low level language, it does not have any natural ways to print values without explicitly casting them into a character string via a format conversion function like printf. The other languages you can just say print @variable and the engine knows to bring the value of the variable, but with C you have to be more specific, because print requires a character string and x is a number, therefore you need to convert x into a character string to print it, either via that function, or a more torturous route such as creating a character array and printing to that array the value of the variable. Could've possibly done a print( itoa(x)); as well.

This is still a little fuzzy but i can understand my way from what you and kalovale said, need to see it in action to completely understand it. Thx for the answers btw.

 Python

Code:

#BUILT-IN FUNCTIONS
def Version1():
    printRange = range(1, 11)
    print(printRange)

Code:

#LIST COMPREHENSION
def Version2():
    printRange = [str(eachValue) for eachValue in range(1, 11)]
    printRange = ', '.join(eachValue)
    print(printRange)

Code:

#GENERATOR OBJECTS
def Version3():
    printGenerator = (str(x) for x in range(1, 11))
    for eachValue in printGenerator:
        print(eachValue)

Code:

#RECURSION
def Version4(currentNumber, endNumber):
    print(currentNumber)
    if currentNumber < endNumber:
        Version4(currentNumber+1, endNumber)
Version4(1, 10)

Code:

#ITERATOR OBJECT
def Version5():
    import itertools
    for eachValue in itertools.count(1):
        print(eachValue)
        if eachValue == 10:
            break

Code:

#ASCII/BINARY CONVERSION
def Version6():
    import string
    for eachLetter in string.ascii_uppercase:
        eachLetter = ord(eachLetter) - 64
        print(eachLetter)
        if eachLetter == 10:
            break

Code:

#FILTER
def Version7(x):
    return x < 11
printRange = filter(Version7, range(1, 25))
print(printRange)

Aww, I was hoping for some degree of creativity from you guys.

Code:

HAI
CAN HAS STDIO?
I HAS A VAR
IM IN YR LOOP
    UPZ VAR!!1
    VISIBLE VAR
    IZ VAR BIGR THAN 10? GTFO. KTHX
KTHX
KTHXBYE

Aww, I was hoping for some degree of creativity from you guys.

Code:

HAI
CAN HAS STDIO?
I HAS A VAR
IM IN YR LOOP
    UPZ VAR!!1
    VISIBLE VAR
    IZ VAR BIGR THAN 10? GTFO. KTHX
KTHX
KTHXBYE

I actually WAS considering posting this one xD

Aww, I was hoping for some degree of creativity from you guys.

You stated elegence was the target, short and succinct.
What did you expect?

Aww, I was hoping for some degree of creativity from you guys.

Code:

HAI
CAN HAS STDIO?
I HAS A VAR
IM IN YR LOOP
    UPZ VAR!!1
    VISIBLE VAR
    IZ VAR BIGR THAN 10? GTFO. KTHX
KTHX
KTHXBYE

Code:

while(!derpington) {
   derp++;
}

Jeez, I gotta re-learn all this stuff. Haven't in years.
I would post binary code but that's too simple compared to what you guys wrote =3=

Jeez, I gotta re-learn all this stuff. Haven't in years.
I would post binary code but that's too simple compared to what you guys wrote =3=

Indeed. Machine code is simpler than .NET

Just for fun

 Joy

Code:

1 [10 <=] [dup put succ] while

Code:

10 [] [put] primrec

Indeed. Machine code is simpler than .NET

:f6:

How so?

vb.net is almost identical to the VB i posted.
Even C# and C++.net work with the C examples I gave.

Sorry, Eosian. Let me clarify.

<sarcasm>
Indeed. Machine code is simpler than .NET
</sarcasm>

I was making fun of his statement that binary code is easier than "the examples posted here".

Ah, OK. Internet. Lack of tone. Programming discussion. Bad chin.