2011-12-28, 03:48 PM
I'm not sure this is even possible.
You can't have more than 1 $.50, because then you'd be able to break $1.
You can't have more than 1 $.25, because then you'd be able to break $.50.
With 1 $.50 and 1 $.25, you need $.40 more in four coins. The only way this is possible is with 4 $.10. This, however, allows you to add up to $.95.
Without one of the $.50 or $.25 (or both of them), it's impossible to add up to $1.15 in only six coins.
Am I interpreting the question incorrectly?..
You can't have more than 1 $.50, because then you'd be able to break $1.
You can't have more than 1 $.25, because then you'd be able to break $.50.
With 1 $.50 and 1 $.25, you need $.40 more in four coins. The only way this is possible is with 4 $.10. This, however, allows you to add up to $.95.
Without one of the $.50 or $.25 (or both of them), it's impossible to add up to $1.15 in only six coins.
Am I interpreting the question incorrectly?..