2011-11-15, 10:57 PM
This is very simple lol.
straight flush
4-of-a-kind = 1 hand of course since you need all 4 of a card.
full house
flush
straight
3-of-a-kind
two pairs
pair
high card
Honestly this isn't statistics if you're looking at probability, it's more like logic. I don't remember specifically what half of those hands are again...
Look at pair. Let's label Spades as A, Clubs as B, Hearts as C, and Diamonds as D.
Let's look at a single card, let's look at 9.
9A and 9B is a pair, 9A and 9C is a pair, 9A and 9D is a pair, 9B and 9C is a pair, 9B and 9D are a pair, and 9C and 9D are a pair. Six distinct sets that are possible involving 9.
Now that is for one number, we have 13 numbers (2-10 + A + K + Q + J). So multiply our 6 sets x 13 different cards = 78 different possible hands for a pair.
That's not really statistics.
straight flush
4-of-a-kind = 1 hand of course since you need all 4 of a card.
full house
flush
straight
3-of-a-kind
two pairs
pair
high card
Honestly this isn't statistics if you're looking at probability, it's more like logic. I don't remember specifically what half of those hands are again...
Look at pair. Let's label Spades as A, Clubs as B, Hearts as C, and Diamonds as D.
Let's look at a single card, let's look at 9.
9A and 9B is a pair, 9A and 9C is a pair, 9A and 9D is a pair, 9B and 9C is a pair, 9B and 9D are a pair, and 9C and 9D are a pair. Six distinct sets that are possible involving 9.
Now that is for one number, we have 13 numbers (2-10 + A + K + Q + J). So multiply our 6 sets x 13 different cards = 78 different possible hands for a pair.
That's not really statistics.