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1st year Physics Question - Difficult 2D-motion
#3
For the second part...The theta that gives the largest angle is always 45 degrees, remember that to heart. The ones that fail are 90 and 0 degrees.

That formula is gay to be honest, use the formula

R = (Vo^2)(sin2Theta)/g

That is, the Range equals the (initial velocity squared) times (the sin of double the angle) all divided by g. The perfect angle will be 45 degrees because double that = sin 90 and the sin of 90 = 1, anything besides 45 degrees will yield a fraction which will make the range shorter.

I wish I had more time to draw you a diagram but I have to go to school.
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1st year Physics Question - Difficult 2D-motion - by OB3LISK - 2011-10-17, 06:50 AM

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