2011-09-08, 07:17 AM
5C2 is just 5!/(3!)(2!) = 120, nCr is n!/(r!)((n-r)!).
If you didn't know, you can work out the probability of activating at least once is 1 - P(not activating at all).
@Shinku: I can probably work out the answer if you give me the conditions to be fulfilled
EDIT: Ninja'd
Wisdom has 5% chance of activating.
p = 0.05
q = 0.95
Buster is 4 hits, so n = 4
If we want to work out at least one proc, work out for r = 0
4C0 (0.05)^0 (0.95)^4
= 0.8145
~81.45% chance of not triggering at all, which means 18.55% of triggering at least once per 4 hits of buster.
Also it should be nCr p^r q^(n-r), baconator25 kinda derped there.
If you didn't know, you can work out the probability of activating at least once is 1 - P(not activating at all).
@Shinku: I can probably work out the answer if you give me the conditions to be fulfilled
EDIT: Ninja'd
Wisdom has 5% chance of activating.
p = 0.05
q = 0.95
Buster is 4 hits, so n = 4
If we want to work out at least one proc, work out for r = 0
4C0 (0.05)^0 (0.95)^4
= 0.8145
~81.45% chance of not triggering at all, which means 18.55% of triggering at least once per 4 hits of buster.
Also it should be nCr p^r q^(n-r), baconator25 kinda derped there.