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20 people in a room. 40% chance two people share a birthday.
#4
1-P(everyone has a different birthday)

Consider person one... he can have any birthday without matching someone

1-365/365 aka 0% 1 person shares a birthday with someone else (makes sense.... there's no one else)

2nd person... any birthday cept the one from the previous person so he has 364/365 options

1- (365*364)/(365*365)

go to 20 people

1- (365*...*346)/(365^20) ~41%
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20 people in a room. 40% chance two people share a birthday. - by shouri - 2011-06-10, 03:22 PM

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