I must be doing something wrong here.

I would factor it out with a u sub:
y=u+2

So... y'=u = x^2-3x?

Wolfram was no help to me at all. ._.[url=http://www.wolframalpha.com/input/?i=derivative+of+%28x%5E2-3x%2B2%29+with+respect+to+%28x%5E2-3x%29][/url]

Um I think that wouldn't work.

Let's say that y = x^5 or something, and that u = x^5, therefore y = u.

y' = 1 ????/??/

(Actually it would be more like dy/du = 1. Don't ask me what that means.)


As for CoB's question, I have never encountered that, so I can't help there.