2010-11-02, 07:28 PM
Hmm just searched wolfram-alpha.
you just use these identities:
e^(i*pi) = -1
e^(i*x) = cos(x) + i*sin(x)
so (-1)^pi = e^(i*pi)^pi = e^(i*pi²
= cos(pi² + i*sin(pi²
so it's the value posted by Corn, yeah.
you just use these identities:
e^(i*pi) = -1
e^(i*x) = cos(x) + i*sin(x)
so (-1)^pi = e^(i*pi)^pi = e^(i*pi²
= cos(pi² + i*sin(pi²so it's the value posted by Corn, yeah.