2010-10-21, 11:19 PM
I can't read the formula... what is "-^3"?
Anyway, you probably want to basically add dx * d/dx (first approximation), then dx^2/2 * d^2/dx^2 (second approximation) and so forth until they become zero.
That is, if you know the value at a point (x = 3, y = 2) and you know the slope (d/dx = 3) then at x = 3.04, you have 0.04*3 + 2 = 2.12 as an approximation of (3.04, 2.12)
It's called the Taylor expansion, f(x + t) = f(x) + t/1!*f'(x) + t^2/2!*f''(x) + t^3/3!*f'''(x) + ...
Anyway, you probably want to basically add dx * d/dx (first approximation), then dx^2/2 * d^2/dx^2 (second approximation) and so forth until they become zero.
That is, if you know the value at a point (x = 3, y = 2) and you know the slope (d/dx = 3) then at x = 3.04, you have 0.04*3 + 2 = 2.12 as an approximation of (3.04, 2.12)
It's called the Taylor expansion, f(x + t) = f(x) + t/1!*f'(x) + t^2/2!*f''(x) + t^3/3!*f'''(x) + ...