2010-10-16, 01:34 PM
2147483647 Wrote:Say you sink a cubical box in the water and it is rotating. The pressure at the bottom of the box is going to be greater than the pressure at the top. The rotational motion is going to lower the fluid pressure in a nonuniform way. Overall, there's no way dP=0.
But it can be treated as if it is for 2 very infinitesimally close volumes, which it has to be for it to be integratable in the first place. If you don't agree with it/understand it, fine, I said it was a cheat (like a lot of physics approximations), but thats exactly where it comes from.

