Ok, I did get a few extras in there.
But there are 3 distinct ways to place the first big L - sitting up, and clockwise/counterclockwise.
![[Image: blocks.gif]](http://img405.imageshack.us/img405/8454/blocks.gif)
If you take black as "top" and grey as "side" these are definitely distinct ways of laying them out.
P(3,2) only applies to the clock/counterclockwise ones - the sitting up version is not rotationally symmetric so it has 9 options since either of the 2 Ls can take all 3 subsets and give a distinct arrangement.
Describing this is easier if I just number the boxes:
![[Image: boxnumbers.gif]](http://img341.imageshack.us/img341/9389/boxnumbers.gif)
1 2 3
4 5 6
7 8 9
10 11 12
Assume it is reconstructed by "sliding" the top down to cover the bottom so 1 is above 7, 2 is above 8, etc.
124 356 and 145 236 are distinct ways of filling the top layer. To avoid being Ls the bottom is then 7 10 11, 8 9 12, and 7 8 10, 9 11 12.
The other 2 "flats" are
1 7 8, 2 3 9, 4 5 10, 6 11 12.
1 2 7, 3 8 9, 4 10 11, 5 6 12.
These are also not rotationally identical so there are definitely 4 possibilities there.
So my current answer is: 6*2 + 9 + 4 = 25.
But there are 3 distinct ways to place the first big L - sitting up, and clockwise/counterclockwise.
![[Image: blocks.gif]](http://img405.imageshack.us/img405/8454/blocks.gif)
If you take black as "top" and grey as "side" these are definitely distinct ways of laying them out.
P(3,2) only applies to the clock/counterclockwise ones - the sitting up version is not rotationally symmetric so it has 9 options since either of the 2 Ls can take all 3 subsets and give a distinct arrangement.
Describing this is easier if I just number the boxes:
![[Image: boxnumbers.gif]](http://img341.imageshack.us/img341/9389/boxnumbers.gif)
1 2 3
4 5 6
7 8 9
10 11 12
Assume it is reconstructed by "sliding" the top down to cover the bottom so 1 is above 7, 2 is above 8, etc.
124 356 and 145 236 are distinct ways of filling the top layer. To avoid being Ls the bottom is then 7 10 11, 8 9 12, and 7 8 10, 9 11 12.
The other 2 "flats" are
1 7 8, 2 3 9, 4 5 10, 6 11 12.
1 2 7, 3 8 9, 4 10 11, 5 6 12.
These are also not rotationally identical so there are definitely 4 possibilities there.
So my current answer is: 6*2 + 9 + 4 = 25.

