Puzzle (coding)

Doesn't it already print one dash without changing the code at all?

 Spoiler

It prints an infinite number of dashes as-is.

EDIT:

 The possible solutions?

1. -i < n (as you said)
2. i < -n
3. n = -20

This is assuming that C can handle negative indices in for loops. I tried compiling it in Java and it won't work. But I barely know anything about C, so if I'm retarded, just let me know.

EDIT2: To do 21 dashes... you have to change 1 character from the original, not 1 from one of the 20-dash solutions, right? Since the latter is a lot easier...

EDIT3:

 OHWAIT

n--

(??!!)

EDIT4: Nvm, my EDIT1 solutions don't work, because then there'd be more than 3 solutions...