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+--- Thread: 0.9999999 = 1 (/showthread.php?tid=5443)
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0.9999999 = 1 - Fiel - 2008-11-19
I'm going to divide by zero on this thread.
0.9999999 = 1 - Lylac - 2008-11-19
butterfli Wrote:
10x - x = (10 - 1)x = 9x
if x = 0.99..., then 9x = (9)(0.99...) != 9
This whole thing revolves around fiddling with invalid operations.
a = b
a^2 = a*b
a^2-b^2 = a*b-b^2
(a+b)(a-b) = b(a-b)
(a+b) = b
a+a = a
2a = a
2 = 1
It's like dividing by 0 and then "proving" that 1 = 2.
![[Image: c53b723c8dfdc96eb7c8f21a4f481b2c.png]](http://upload.wikimedia.org/math/c/5/3/c53b723c8dfdc96eb7c8f21a4f481b2c.png)
your proof that 2=1 is invalid since if a = b, then a-b = 0 and the whole thing becomes 0; you'd also need to divide by 0 in the 4th line, which isn't valid. The proof that 0.99...=1 doesn't divide by 0.
err, didn't see this thread was locked.